从电容和电压计算电容器能量的在线计算器和 Python 代码

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You can enter values with SI suffixes like 12.2m (equivalent to 0.012) or 14k (14000) or 32u (0.000032).
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C ⚠

V ⚠

公式

$$E = \frac{1}{2}\cdot{}C\cdot{}U_p^2$$

Python 代码

你可以像这样使用 UliEngineering 库：

capacitor_energy_calculator.py

from UliEngineering.Electronics.Capacitors import capacitor_energy
from UliEngineering.EngineerIO import auto_format, auto_print

# 这些是等效的：
energy = capacitor_energy("100 uF", "24 V") # energy = 0.0288 (J)
energy = capacitor_energy(100e-6, 24.0) # energy = 0.0288 (J)

# ... 或获取人类可读的值：
energy_str = auto_format(capacitor_energy, "100 uF", "24 V") # "28.8 mJ"
# ... 或直接打印
auto_print(capacitor_energy, "100 uF", "24 V") # prints "28.8 mJ"

from UliEngineering.Electronics.Capacitors import capacitor_energy
from UliEngineering.EngineerIO import auto_format, auto_print

# 这些是等效的：
energy = capacitor_energy("100 uF", "24 V") # energy = 0.0288 (J)
energy = capacitor_energy(100e-6, 24.0) # energy = 0.0288 (J)

# ... 或获取人类可读的值：
energy_str = auto_format(capacitor_energy, "100 uF", "24 V") # "28.8 mJ"
# ... 或直接打印
auto_print(capacitor_energy, "100 uF", "24 V") # prints "28.8 mJ"

如果你不能使用 UliEngineering，使用此 Python 函数：

capacitor_energy_uli.py

def capacitor_energy(capacitance, voltage):
    return 0.5*capacitance*voltage*voltage

# 用法示例：
print(capacitor_energy(100e-6, 24.0)) # 打印 0.0288 (J)

def capacitor_energy(capacitance, voltage):
    return 0.5*capacitance*voltage*voltage

# 用法示例：
print(capacitor_energy(100e-6, 24.0)) # 打印 0.0288 (J)

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